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2x^2-480x=19175
We move all terms to the left:
2x^2-480x-(19175)=0
a = 2; b = -480; c = -19175;
Δ = b2-4ac
Δ = -4802-4·2·(-19175)
Δ = 383800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{383800}=\sqrt{100*3838}=\sqrt{100}*\sqrt{3838}=10\sqrt{3838}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-480)-10\sqrt{3838}}{2*2}=\frac{480-10\sqrt{3838}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-480)+10\sqrt{3838}}{2*2}=\frac{480+10\sqrt{3838}}{4} $
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